WebLet y=x 2−8x+17=(x 2−2⋅4⋅x+4 2)+1=(x−4) 2+1We know that if x is a real number then x 2≥0⇒(x−4) 2≥0Hence minimum value of y is 0+1=1. WebIf x is real, the maximum value of 3x2+9x+73x2+9x+17 is 2997 83 AIEEE AIEEE 2006 Complex Numbers and Quadratic Equations Report Error A 41 B 41 C 1 D 717 Solution: y = 3x2+9x+73x2+9x+17 3x2(y−1)+9x(y− 1)+7y −17 = 0 D ≥ 0 ∵ x is real 81(y −1)2 − 4×3(y−1)(7y −17) ≥ 0 ⇒ (y −1)(y −41) ≤ 0 ⇒ 1 ≤ y ≤ 41 ∴ Max value of y is 41

If `x` is real, then the minimum value of the expression `x^2 …

Web20 dec. 2024 · Show that the maximum value of (1/x)x is e1/e. LIVE Course for free. Rated by 1 million+ students Get app now Login. Remember. Register; ... Let M and m be respectively the absolute maximum and the absolute minimum values of the function, asked Jan 19, 2024 in Limit, ... (17.6k) Artificial Intelligence (AI) (1.4k) Information ... WebAlgebra Solve for x Calculator Step 1: Enter the Equation you want to solve into the editor. The equation calculator allows you to take a simple or complex equation and solve by … f140rgb nzxt

The maximum value of - x^2 - 8x + 17 is - Toppr

WebTherefore function has minima at x = 5, So, now the minimum value of the function will be f ( x) m i n = 5 2 + 250 5 = 25 + 50 = 75 Therefore the minimum value of the function is 75. Hence option A, 75 is the correct answer. Suggest Corrections 0 Similar questions Q. The minimum value of 2 x2+x−1 is Q. Find the minimum value of (5+x)(2+x)(1+x). Q. WebSince value of f ' ' ( x) is positive at x = 5 ,. Therefore function has minima at x = 5, So, now the minimum value of the function will be. f ( x) m i n = 5 2 + 250 5 = 25 + 50 = 75. … Web19 sep. 2024 · Let f(x)= x 2 – 8x + 17. Applying the first derivative we get. Applying the derivative, ⇒ f' (x)=2x-8. Putting f’(x)=0,we get. 2x-8=0. ⇒ 2x=8. ⇒ x=4. Therefore the … hindi bewafai gana